﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>沪江博客-winjiy -文章分类-算法</title><link>http://blog.hjenglish.com/leojay/category/10197.html</link><description>好好学习，天天向上！珍惜身边的一切，过好每一天！</description><language>zh-cn</language><lastBuildDate>Sat, 07 Feb 2009 22:52:17 GMT</lastBuildDate><pubDate>Sat, 07 Feb 2009 22:52:17 GMT</pubDate><ttl>60</ttl><item><title>如何计算平面n个圆相交的公共部分的面积 </title><link>http://blog.hjenglish.com/leojay/articles/171164.html</link><dc:creator>winjiy</dc:creator><author>winjiy</author><pubDate>Sun, 13 Nov 2005 18:51:00 GMT</pubDate><guid>http://blog.hjenglish.com/leojay/articles/171164.html</guid><wfw:comment>http://blog.hjenglish.com/leojay/comments/171164.html</wfw:comment><comments>http://blog.hjenglish.com/leojay/articles/171164.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://blog.hjenglish.com/leojay/comments/commentRss/171164.html</wfw:commentRss><trackback:ping>http://blog.hjenglish.com/leojay/services/trackbacks/171164.html</trackback:ping><description><![CDATA[N个任意圆相交求公共面积的问题必须注意到如下一：凸体和凸体相交依然是凸体，多元相交后也是凸体二：多元相交结果，必然是由圆弧所组成，三：最终的相交面积为各个子圆弧的弓形面积 + 内部凸多边形的面积要解决这个问题，要解决下面几个问题：第一个：圆弧的表达方法Arc(圆心位置，半径，开始角度和结束角度，P1， P2)&nbsp;&nbsp; p1，p2是两个交点的位置交点表达：&nbsp;&nbs...&nbsp;&nbsp;<a href='http://blog.hjenglish.com/leojay/articles/171164.html'>阅读全文</a><img src ="http://blog.hjenglish.com/leojay/aggbug/171164.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://blog.hjenglish.com/leojay/" target="_blank">winjiy</a> 2005-11-14 02:51 <a href="http://blog.hjenglish.com/leojay/articles/171164.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>